Average Speed With Stops: Formula and Worked Examples
Calculate average speed across several journey legs and rest stops. Follow worked examples and avoid averaging speed readings or confusing minutes with hours.
Average speed with stops equals total distance divided by total elapsed time, including the stops. If you travel 150 km in three hours from departure to arrival, your trip average is 50 km/h even if your speed while moving was higher.
The common mistake is to average the speed readings instead of calculating the time spent at each speed. That shortcut only works under specific conditions, such as spending equal amounts of time at each speed.
Start with the quantity you want
Two useful averages answer different questions:
- Moving average speed: distance divided by time actually moving.
- Overall trip average speed: distance divided by the full departure-to-arrival time, including breaks and other stops.
Label the result so another person knows which one you calculated. A journey planner using moving time will underestimate elapsed time if you forget to add stops.
Use kilometres and hours for the worked examples below, which produce km/h. Convert minutes into a fraction of an hour before dividing.
Example 1: One journey with a rest stop
Suppose a trip covers 150 km at a moving average of 60 km/h, followed by a total of 30 minutes stopped along the way.
| Calculation | Working | Result |
|---|---|---|
| Moving time | 150 ÷ 60 | 2.5 hours |
| Stop time | 30 ÷ 60 | 0.5 hours |
| Total elapsed time | 2.5 + 0.5 | 3 hours |
| Overall average speed | 150 ÷ 3 | 50 km/h |
The stop adds time but no distance. That is why the overall average falls below the moving average.
In the speed, distance and time calculator, choose speed, set distance to 150 km, keep speed units at km/h, and enter three hours. This recreates the overall result without pretending the vehicle travelled during the break.
Example 2: Different speeds over different distances
Consider two legs:
| Leg | Distance | Speed | Time |
|---|---|---|---|
| First | 120 km | 60 km/h | 2 hours |
| Second | 120 km | 120 km/h | 1 hour |
| Total | 240 km | — | 3 hours |
Average speed is 240 ÷ 3 = 80 km/h.
Simply averaging 60 and 120 gives 90 km/h, which is wrong for this journey. The slower leg takes twice as long. The journey spends more time at the lower speed, so it must influence the average more heavily.
This is an arithmetic example, not a suggested driving speed. When planning actual travel, use realistic conditions and applicable speed limits.
When averaging two speeds does work
If you spend one hour at 60 km/h and one hour at 120 km/h, the distances are 60 km and 120 km. Total distance is 180 km and total time is two hours, giving 90 km/h.
Here, averaging the speed values happens to work because the durations are equal. Equal distance is not the same condition as equal time.
For equal distances at two positive speeds, the combined average is 2 × speed 1 × speed 2 ÷ (speed 1 + speed 2). That gives 80 km/h for 60 and 120. The distance-over-time method is usually easier to extend when the trip contains more legs or stops.
Example 3: A multi-leg trip with two breaks
Suppose you plan 90 km at 60 km/h and another 60 km at 40 km/h. You also allow a 20-minute stop and a 10-minute stop.
- First-leg time:
90 ÷ 60 = 1.5 hours. - Second-leg time:
60 ÷ 40 = 1.5 hours. - Total stop time:
(20 + 10) ÷ 60 = 0.5 hours. - Total elapsed time:
1.5 + 1.5 + 0.5 = 3.5 hours. - Overall average:
(90 + 60) ÷ 3.5 ≈ 42.86 km/h.
The moving average is 50 km/h, but the overall average is approximately 42.86 km/h. Both numbers are valid when their time basis is stated.
UtilVox's multi-leg planner sums travel time from the distance and speed entered for each leg. It has no separate stop-duration field. Add breaks yourself, then enter the full distance and elapsed time in the main speed calculation. Do not represent a stop as a zero-speed leg: it is a duration to add, not a distance-over-zero calculation.
Minutes are not decimal hundredths
One hour and 30 minutes is 1.5 hours, not 1.30 hours. The conversion is 1 + 30 ÷ 60.
| Clock duration | Decimal hours |
|---|---|
| 1 hour 15 minutes | 1.25 |
| 1 hour 30 minutes | 1.5 |
| 1 hour 45 minutes | 1.75 |
| 2 hours 20 minutes | Approximately 2.3333 |
Keep extra precision until the final answer. Rounding every leg's time first can introduce unnecessary differences when you add many legs together.
The calculator provides separate hour, minute and second inputs, so you can enter a duration directly. For these examples, keep the distance and speed settings at km and km/h throughout. If your source uses another unit system, convert it consistently with the unit converter before using this workflow.
Check whether your answer makes sense
An overall average that includes stops should not exceed the moving average for the same trip. With positive travel times, a moving average across several legs should lie between the lowest and highest leg speeds.
Zero elapsed time does not produce a meaningful finite speed for a positive distance. Check inputs instead of accepting a calculator's fallback value. Negative distance and negative travel durations also do not describe this ordinary journey-planning problem.
Finally, average speed is not average velocity: speed uses total distance travelled, while velocity depends on displacement and direction. A round trip can end where it began while still covering a substantial distance.
Try your own leg distances in the speed calculator, add stops to the elapsed time, and label the result as a trip average. The time definition is what makes the answer useful.